Base | Representation |
---|---|
bin | 111100100011010010… |
… | …1000000001100100110 |
3 | 110102122020021010101121 |
4 | 1321012211000030212 |
5 | 4112301434433014 |
6 | 135423021044154 |
7 | 12252225214114 |
oct | 1710645001446 |
9 | 412566233347 |
10 | 130033124134 |
11 | 50168343851 |
12 | 2124b9b665a |
13 | c353a01804 |
14 | 6417a4cab4 |
15 | 35b0c08124 |
hex | 1e46940326 |
130033124134 has 24 divisors (see below), whose sum is σ = 207346461480. Its totient is φ = 61148246016.
The previous prime is 130033124107. The next prime is 130033124153. The reversal of 130033124134 is 431421330031.
It is a super-2 number, since 2×1300331241342 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130033124099 and 130033124108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 734569 + ... + 894235.
It is an arithmetic number, because the mean of its divisors is an integer number (8639435895).
Almost surely, 2130033124134 is an apocalyptic number.
130033124134 is a deficient number, since it is larger than the sum of its proper divisors (77313337346).
130033124134 is a wasteful number, since it uses less digits than its factorization.
130033124134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 161112 (or 161095 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 130033124134 its reverse (431421330031), we get a palindrome (561454454165).
The spelling of 130033124134 in words is "one hundred thirty billion, thirty-three million, one hundred twenty-four thousand, one hundred thirty-four".
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