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130039967 is a prime number
BaseRepresentation
bin1111100000001…
…00000010011111
3100001200201022002
413300010002133
5231242234332
620523112515
73136215161
oct760040237
9301621262
10130039967
1167449a52
123767273b
1320c30a35
14133b0931
15b63a562
hex7c0409f

130039967 has 2 divisors, whose sum is σ = 130039968. Its totient is φ = 130039966.

The previous prime is 130039957. The next prime is 130039969. The reversal of 130039967 is 769930031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130039967 - 210 = 130038943 is a prime.

It is a super-2 number, since 2×1300399672 = 33820786034722178, which contains 22 as substring.

Together with 130039969, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130039967.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130039969) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65019983 + 65019984.

It is an arithmetic number, because the mean of its divisors is an integer number (65019984).

Almost surely, 2130039967 is an apocalyptic number.

130039967 is a deficient number, since it is larger than the sum of its proper divisors (1).

130039967 is an equidigital number, since it uses as much as digits as its factorization.

130039967 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30618, while the sum is 38.

The square root of 130039967 is about 11403.5067851955. The cubic root of 130039967 is about 506.6316106189.

Adding to 130039967 its reverse (769930031), we get a palindrome (899969998).

The spelling of 130039967 in words is "one hundred thirty million, thirty-nine thousand, nine hundred sixty-seven".