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13004010 = 233548163
BaseRepresentation
bin110001100110…
…110011101010
3220110200011000
4301212303222
511312112020
61142415430
7215350365
oct61466352
926420130
1013004010
117382118
124431576
132903ca6
141a270dc
15121d090
hexc66cea

13004010 has 32 divisors (see below), whose sum is σ = 34678080. Its totient is φ = 3467664.

The previous prime is 13003987. The next prime is 13004051. The reversal of 13004010 is 1040031.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a junction number, because it is equal to n+sod(n) for n = 13003983 and 13004001.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23812 + ... + 24351.

It is an arithmetic number, because the mean of its divisors is an integer number (1083690).

Almost surely, 213004010 is an apocalyptic number.

13004010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13004010 is an abundant number, since it is smaller than the sum of its proper divisors (21674070).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13004010 is a wasteful number, since it uses less digits than its factorization.

13004010 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48179 (or 48173 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 9.

The square root of 13004010 is about 3606.1073195345. The cubic root of 13004010 is about 235.1576428305.

Adding to 13004010 its reverse (1040031), we get a palindrome (14044041).

The spelling of 13004010 in words is "thirteen million, four thousand, ten".

Divisors: 1 2 3 5 6 9 10 15 18 27 30 45 54 90 135 270 48163 96326 144489 240815 288978 433467 481630 722445 866934 1300401 1444890 2167335 2600802 4334670 6502005 13004010