1300426117 has 2 divisors, whose sum is σ = 1300426118. Its totient is φ = 1300426116.

The previous prime is 1300426111. The next prime is 1300426123. The reversal of 1300426117 is 7116240031.

It is a balanced prime because it is at equal distance from previous prime (1300426111) and next prime (1300426123).

It can be written as a sum of positive squares in only one way, i.e., 705114916 + 595311201 = 26554^2 + 24399^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300426117 - 2³ = 1300426109 is a prime.

It is a super-2 number, since 2×1300426117² = 3382216171551395378, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300426091 and 1300426100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300426111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650213058 + 650213059.

It is an arithmetic number, because the mean of its divisors is an integer number (650213059).

Almost surely, 2^1300426117 is an apocalyptic number.

It is an amenable number.

1300426117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300426117 is an equidigital number, since it uses as much as digits as its factorization.

1300426117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

The square root of 1300426117 is about 36061.4214500760. The cubic root of 1300426117 is about 1091.5121164605.

Adding to 1300426117 its reverse (7116240031), we get a palindrome (8416666148).

The spelling of 1300426117 in words is "one billion, three hundred million, four hundred twenty-six thousand, one hundred seventeen".