Base | Representation |
---|---|
bin | 1011110100111101001011… |
… | …0110001101001101100000 |
3 | 1201001012122020022221222101 |
4 | 2331033102312031031200 |
5 | 3201031004234231430 |
6 | 43354050201220144 |
7 | 2511352145214415 |
oct | 275172266151540 |
9 | 51035566287871 |
10 | 13004403430240 |
11 | 4164155792042 |
12 | 1560410491654 |
13 | 73440504c841 |
14 | 32d5b8b9410c |
15 | 17841b04bdca |
hex | bd3d2d8d360 |
13004403430240 has 24 divisors (see below), whose sum is σ = 30722903104320. Its totient is φ = 5201761372032.
The previous prime is 13004403430189. The next prime is 13004403430243. The reversal of 13004403430240 is 4203430440031.
It is a super-2 number, since 2×130044034302402 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13004403430199 and 13004403430208.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13004403430243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40638760560 + ... + 40638760879.
It is an arithmetic number, because the mean of its divisors is an integer number (1280120962680).
Almost surely, 213004403430240 is an apocalyptic number.
13004403430240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13004403430240 is an abundant number, since it is smaller than the sum of its proper divisors (17718499674080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13004403430240 is an equidigital number, since it uses as much as digits as its factorization.
13004403430240 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81277521454 (or 81277521446 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 13004403430240 its reverse (4203430440031), we get a palindrome (17207833870271).
The spelling of 13004403430240 in words is "thirteen trillion, four billion, four hundred three million, four hundred thirty thousand, two hundred forty".
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