Base | Representation |
---|---|
bin | 1011110100111110001011… |
… | …0000011100001011111010 |
3 | 1201001020022211121002202212 |
4 | 2331033202300130023322 |
5 | 3201032031102313140 |
6 | 43354132454255122 |
7 | 2511361566064325 |
oct | 275174260341372 |
9 | 51036284532685 |
10 | 13004670354170 |
11 | 4164282424a30 |
12 | 15604859574a2 |
13 | 7344484394b1 |
14 | 32d6023d77bc |
15 | 1784346c5765 |
hex | bd3e2c1c2fa |
13004670354170 has 32 divisors (see below), whose sum is σ = 26880466956480. Its totient is φ = 4480077824640.
The previous prime is 13004670354157. The next prime is 13004670354191. The reversal of 13004670354170 is 7145307640031.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3111163067 + ... + 3111167246.
It is an arithmetic number, because the mean of its divisors is an integer number (840014592390).
Almost surely, 213004670354170 is an apocalyptic number.
13004670354170 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13004670354170 is an abundant number, since it is smaller than the sum of its proper divisors (13875796602310).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13004670354170 is a wasteful number, since it uses less digits than its factorization.
13004670354170 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6222330350.
The product of its (nonzero) digits is 211680, while the sum is 41.
The spelling of 13004670354170 in words is "thirteen trillion, four billion, six hundred seventy million, three hundred fifty-four thousand, one hundred seventy".
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