Base | Representation |
---|---|
bin | 10010111011110000011… |
… | …000101011000100011100 |
3 | 11121101101210212222001122 |
4 | 102323300120223010130 |
5 | 132304134424414400 |
6 | 2433420105430112 |
7 | 163000540032260 |
oct | 22736030530434 |
9 | 4541353788048 |
10 | 1301113123100 |
11 | 46188749003a |
12 | 1901b819b338 |
13 | 959048c136b |
14 | 46d8d3420a0 |
15 | 23ca19ee685 |
hex | 12ef062b11c |
1301113123100 has 72 divisors (see below), whose sum is σ = 3242975769600. Its totient is φ = 443854192320.
The previous prime is 1301113123073. The next prime is 1301113123103. The reversal of 1301113123100 is 13213111031.
It is a super-2 number, since 2×13011131231002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1301113123103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4530884 + ... + 4809483.
Almost surely, 21301113123100 is an apocalyptic number.
1301113123100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1301113123100 is an abundant number, since it is smaller than the sum of its proper divisors (1941862646500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1301113123100 is a wasteful number, since it uses less digits than its factorization.
1301113123100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9340587 (or 9340580 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1301113123100 its reverse (13213111031), we get a palindrome (1314326234131).
The spelling of 1301113123100 in words is "one trillion, three hundred one billion, one hundred thirteen million, one hundred twenty-three thousand, one hundred".
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