13011344040 has 32 divisors (see below), whose sum is σ = 39034032480. Its totient is φ = 3469691712.

The previous prime is 13011343987. The next prime is 13011344051. The reversal of 13011344040 is 4044311031.

It is a junction number, because it is equal to n+sod(n) for n = 13011343998 and 13011344016.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 54213814 + ... + 54214053.

It is an arithmetic number, because the mean of its divisors is an integer number (1219813515).

Almost surely, 2^13011344040 is an apocalyptic number.

13011344040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13011344040 is an abundant number, since it is smaller than the sum of its proper divisors (26022688440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13011344040 is a wasteful number, since it uses less digits than its factorization.

13011344040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108427881 (or 108427877 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 13011344040 its reverse (4044311031), we get a palindrome (17055655071).

The spelling of 13011344040 in words is "thirteen billion, eleven million, three hundred forty-four thousand, forty".