Base | Representation |
---|---|
bin | 11000001111000101… |
… | …00001110000001110 |
3 | 1020120210020021110211 |
4 | 30013202201300032 |
5 | 203121404043200 |
6 | 5551035153034 |
7 | 640302006661 |
oct | 140742416016 |
9 | 36523207424 |
10 | 13011393550 |
11 | 5577657611 |
12 | 26315a577a |
13 | 12c486094c |
14 | 8b60936d8 |
15 | 512452aba |
hex | 3078a1c0e |
13011393550 has 24 divisors (see below), whose sum is σ = 24204421800. Its totient is φ = 5203862880.
The previous prime is 13011393533. The next prime is 13011393599. The reversal of 13011393550 is 5539311031.
It is a super-2 number, since 2×130113935502 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 535056 + ... + 558844.
It is an arithmetic number, because the mean of its divisors is an integer number (1008517575).
Almost surely, 213011393550 is an apocalyptic number.
13011393550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13011393550 is a deficient number, since it is larger than the sum of its proper divisors (11193028250).
13011393550 is a wasteful number, since it uses less digits than its factorization.
13011393550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34740 (or 34735 counting only the distinct ones).
The product of its (nonzero) digits is 6075, while the sum is 31.
The spelling of 13011393550 in words is "thirteen billion, eleven million, three hundred ninety-three thousand, five hundred fifty".
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