Base | Representation |
---|---|
bin | 1011110101011001100100… |
… | …0101111111011101111000 |
3 | 1201001221022100120120111002 |
4 | 2331112121011333131320 |
5 | 3201142111223034222 |
6 | 43401350321424132 |
7 | 2512042044462134 |
oct | 275263105773570 |
9 | 51057270516432 |
10 | 13012024424312 |
11 | 4167406623751 |
12 | 156199879b048 |
13 | 73504abc20a4 |
14 | 32dadcda03c4 |
15 | 17871512e392 |
hex | bd59917f778 |
13012024424312 has 32 divisors (see below), whose sum is σ = 25232043110400. Its totient is φ = 6286984046304.
The previous prime is 13012024424309. The next prime is 13012024424317. The reversal of 13012024424312 is 21342442021031.
It is a super-3 number, since 3×130120244243123 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13012024424317) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 218998448 + ... + 219057855.
It is an arithmetic number, because the mean of its divisors is an integer number (788501347200).
Almost surely, 213012024424312 is an apocalyptic number.
It is an amenable number.
13012024424312 is a deficient number, since it is larger than the sum of its proper divisors (12220018686088).
13012024424312 is a wasteful number, since it uses less digits than its factorization.
13012024424312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 438056435 (or 438056431 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 13012024424312 its reverse (21342442021031), we get a palindrome (34354466445343).
The spelling of 13012024424312 in words is "thirteen trillion, twelve billion, twenty-four million, four hundred twenty-four thousand, three hundred twelve".
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