Base | Representation |
---|---|
bin | 111100100101111101… |
… | …1111001110001110000 |
3 | 110102212111101222001110 |
4 | 1321023323321301300 |
5 | 4112442442410412 |
6 | 135435551433320 |
7 | 12254366235342 |
oct | 1711373716160 |
9 | 412774358043 |
10 | 130123013232 |
11 | 50204059863 |
12 | 21275b25840 |
13 | c369515124 |
14 | 642596b292 |
15 | 35b8a61d3c |
hex | 1e4bef9c70 |
130123013232 has 80 divisors (see below), whose sum is σ = 357913520640. Its totient is φ = 40594799616.
The previous prime is 130123013219. The next prime is 130123013239. The reversal of 130123013232 is 232310321031.
It is a junction number, because it is equal to n+sod(n) for n = 130123013199 and 130123013208.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130123013239) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 299368 + ... + 591495.
It is an arithmetic number, because the mean of its divisors is an integer number (4473919008).
Almost surely, 2130123013232 is an apocalyptic number.
130123013232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
130123013232 is an abundant number, since it is smaller than the sum of its proper divisors (227790507408).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130123013232 is a wasteful number, since it uses less digits than its factorization.
130123013232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 891070 (or 891064 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 130123013232 its reverse (232310321031), we get a palindrome (362433334263).
The spelling of 130123013232 in words is "one hundred thirty billion, one hundred twenty-three million, thirteen thousand, two hundred thirty-two".
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