130123241301437 has 2 divisors, whose sum is σ = 130123241301438. Its totient is φ = 130123241301436.

The previous prime is 130123241301367. The next prime is 130123241301439. The reversal of 130123241301437 is 734103142321031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128807382243556 + 1315859057881 = 11349334^2 + 1147109^2 .

It is a cyclic number.

It is not a de Polignac number, because 130123241301437 - 2¹² = 130123241297341 is a prime.

Together with 130123241301439, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130123241301397 and 130123241301406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130123241301439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65061620650718 + 65061620650719.

It is an arithmetic number, because the mean of its divisors is an integer number (65061620650719).

Almost surely, 2^{130123241301437} is an apocalyptic number.

It is an amenable number.

130123241301437 is a deficient number, since it is larger than the sum of its proper divisors (1).

130123241301437 is an equidigital number, since it uses as much as digits as its factorization.

130123241301437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288, while the sum is 35.

Adding to 130123241301437 its reverse (734103142321031), we get a palindrome (864226383622468).

The spelling of 130123241301437 in words is "one hundred thirty trillion, one hundred twenty-three billion, two hundred forty-one million, three hundred one thousand, four hundred thirty-seven".