Base | Representation |
---|---|
bin | 11000001111010100… |
… | …10110011000100011 |
3 | 1020120221002110100021 |
4 | 30013222112120203 |
5 | 203122420203011 |
6 | 5551151134311 |
7 | 640325310232 |
oct | 140752263043 |
9 | 36527073307 |
10 | 13013444131 |
11 | 5578828206 |
12 | 2632214397 |
13 | 12c50cb0cc |
14 | 8b6468b19 |
15 | 51270a471 |
hex | 307a96623 |
13013444131 has 2 divisors, whose sum is σ = 13013444132. Its totient is φ = 13013444130.
The previous prime is 13013444117. The next prime is 13013444149. The reversal of 13013444131 is 13144431031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13013444131 - 227 = 12879226403 is a prime.
It is a super-2 number, since 2×130134441312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13013444096 and 13013444105.
It is not a weakly prime, because it can be changed into another prime (13013447131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506722065 + 6506722066.
It is an arithmetic number, because the mean of its divisors is an integer number (6506722066).
Almost surely, 213013444131 is an apocalyptic number.
13013444131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13013444131 is an equidigital number, since it uses as much as digits as its factorization.
13013444131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13013444131 its reverse (13144431031), we get a palindrome (26157875162).
The spelling of 13013444131 in words is "thirteen billion, thirteen million, four hundred forty-four thousand, one hundred thirty-one".
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