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13013444149 is a prime number
BaseRepresentation
bin11000001111010100…
…10110011000110101
31020120221002110100221
430013222112120311
5203122420203044
65551151134341
7640325310256
oct140752263065
936527073327
1013013444149
115578828222
1226322143b1
1312c50cb114
148b6468b2d
1551270a484
hex307a96635

13013444149 has 2 divisors, whose sum is σ = 13013444150. Its totient is φ = 13013444148.

The previous prime is 13013444131. The next prime is 13013444167. The reversal of 13013444149 is 94144431031.

13013444149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (13013444131) and next prime (13013444167).

It can be written as a sum of positive squares in only one way, i.e., 12812655249 + 200788900 = 113193^2 + 14170^2 .

It is a cyclic number.

It is not a de Polignac number, because 13013444149 - 25 = 13013444117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13013444179) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506722074 + 6506722075.

It is an arithmetic number, because the mean of its divisors is an integer number (6506722075).

Almost surely, 213013444149 is an apocalyptic number.

It is an amenable number.

13013444149 is a deficient number, since it is larger than the sum of its proper divisors (1).

13013444149 is an equidigital number, since it uses as much as digits as its factorization.

13013444149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 34.

The spelling of 13013444149 in words is "thirteen billion, thirteen million, four hundred forty-four thousand, one hundred forty-nine".