Base | Representation |
---|---|
bin | 111100100110100010… |
… | …1001000110001101101 |
3 | 110102220211112022200121 |
4 | 1321031011020301231 |
5 | 4113012401224211 |
6 | 135441515124541 |
7 | 12255021354133 |
oct | 1711505106155 |
9 | 412824468617 |
10 | 130142211181 |
11 | 50213981534 |
12 | 21280443751 |
13 | c3704a7468 |
14 | 6428327753 |
15 | 35ba5a5271 |
hex | 1e4d148c6d |
130142211181 has 2 divisors, whose sum is σ = 130142211182. Its totient is φ = 130142211180.
The previous prime is 130142211169. The next prime is 130142211229. The reversal of 130142211181 is 181112241031.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125964657225 + 4177553956 = 354915^2 + 64634^2 .
It is a cyclic number.
It is not a de Polignac number, because 130142211181 - 27 = 130142211053 is a prime.
It is a super-2 number, since 2×1301422111812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130142211781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65071105590 + 65071105591.
It is an arithmetic number, because the mean of its divisors is an integer number (65071105591).
Almost surely, 2130142211181 is an apocalyptic number.
It is an amenable number.
130142211181 is a deficient number, since it is larger than the sum of its proper divisors (1).
130142211181 is an equidigital number, since it uses as much as digits as its factorization.
130142211181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 25.
The spelling of 130142211181 in words is "one hundred thirty billion, one hundred forty-two million, two hundred eleven thousand, one hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •