Base | Representation |
---|---|
bin | 10010111100000100101… |
… | …110101000110001100101 |
3 | 11121102021121002220111202 |
4 | 102330010232220301211 |
5 | 132310334313101224 |
6 | 2433514021012245 |
7 | 163012153042142 |
oct | 22740456506145 |
9 | 4542247086452 |
10 | 1301454425189 |
11 | 461a42104386 |
12 | 190292554085 |
13 | 9595a520569 |
14 | 46dc27c73c9 |
15 | 23cc196aeae |
hex | 12f04ba8c65 |
1301454425189 has 2 divisors, whose sum is σ = 1301454425190. Its totient is φ = 1301454425188.
The previous prime is 1301454425147. The next prime is 1301454425191. The reversal of 1301454425189 is 9815244541031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1269547534564 + 31906890625 = 1126742^2 + 178625^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1301454425189 is a prime.
Together with 1301454425191, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1301454325189) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650727212594 + 650727212595.
It is an arithmetic number, because the mean of its divisors is an integer number (650727212595).
Almost surely, 21301454425189 is an apocalyptic number.
It is an amenable number.
1301454425189 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301454425189 is an equidigital number, since it uses as much as digits as its factorization.
1301454425189 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 691200, while the sum is 47.
The spelling of 1301454425189 in words is "one trillion, three hundred one billion, four hundred fifty-four million, four hundred twenty-five thousand, one hundred eighty-nine".
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