130211343334440 has 64 divisors (see below), whose sum is σ = 434037811118400. Its totient is φ = 34723024888896.

The previous prime is 130211343334337. The next prime is 130211343334481. The reversal of 130211343334440 is 44433343112031.

130211343334440 is a `hidden beast` number, since 1 + 3 + 0 + 21 + 134 + 33 + 34 + 440 = 666.

It is a super-2 number, since 2×130211343334440² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 130211343334395 and 130211343334404.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60283028242 + ... + 60283030401.

It is an arithmetic number, because the mean of its divisors is an integer number (6781840798725).

Almost surely, 2^{130211343334440} is an apocalyptic number.

130211343334440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130211343334440 is an abundant number, since it is smaller than the sum of its proper divisors (303826467783960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130211343334440 is a wasteful number, since it uses less digits than its factorization.

130211343334440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120566058663 (or 120566058653 counting only the distinct ones).

The product of its (nonzero) digits is 124416, while the sum is 36.

Adding to 130211343334440 its reverse (44433343112031), we get a palindrome (174644686446471).

The spelling of 130211343334440 in words is "one hundred thirty trillion, two hundred eleven billion, three hundred forty-three million, three hundred thirty-four thousand, four hundred forty".