Base | Representation |
---|---|
bin | 111100101000100111… |
… | …1011010000011000110 |
3 | 110110002200212120201122 |
4 | 1321101033122003012 |
5 | 4113133233342410 |
6 | 135452451153542 |
7 | 12256526561546 |
oct | 1712117320306 |
9 | 413080776648 |
10 | 130212012230 |
11 | 5024a317053 |
12 | 2129b8a58b2 |
13 | c381aa6561 |
14 | 64336d7326 |
15 | 35c1791e55 |
hex | 1e513da0c6 |
130212012230 has 32 divisors (see below), whose sum is σ = 235316976768. Its totient is φ = 51877065600.
The previous prime is 130212012209. The next prime is 130212012239. The reversal of 130212012230 is 32210212031.
130212012230 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 130212012199 and 130212012208.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130212012239) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14252744 + ... + 14261876.
It is an arithmetic number, because the mean of its divisors is an integer number (7353655524).
Almost surely, 2130212012230 is an apocalyptic number.
130212012230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130212012230 is a deficient number, since it is larger than the sum of its proper divisors (105104964538).
130212012230 is a wasteful number, since it uses less digits than its factorization.
130212012230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14672.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 130212012230 its reverse (32210212031), we get a palindrome (162422224261).
The spelling of 130212012230 in words is "one hundred thirty billion, two hundred twelve million, twelve thousand, two hundred thirty".
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