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13021284252917 is a prime number
BaseRepresentation
bin1011110101111100000100…
…0001011011110011110101
31201002211012200120121100002
42331133001001123303311
53201320042232043132
643405521224001045
72512520363642033
oct275370101336365
951084180517302
1013021284252917
114170328550a66
121563741900185
13735b95446605
1433033aacd553
15178aa8032262
hexbd7c105bcf5

13021284252917 has 2 divisors, whose sum is σ = 13021284252918. Its totient is φ = 13021284252916.

The previous prime is 13021284252901. The next prime is 13021284252923. The reversal of 13021284252917 is 71925248212031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12976774224241 + 44510028676 = 3602329^2 + 210974^2 .

It is a cyclic number.

It is not a de Polignac number, because 13021284252917 - 24 = 13021284252901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13021284254917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6510642126458 + 6510642126459.

It is an arithmetic number, because the mean of its divisors is an integer number (6510642126459).

Almost surely, 213021284252917 is an apocalyptic number.

It is an amenable number.

13021284252917 is a deficient number, since it is larger than the sum of its proper divisors (1).

13021284252917 is an equidigital number, since it uses as much as digits as its factorization.

13021284252917 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 483840, while the sum is 47.

The spelling of 13021284252917 in words is "thirteen trillion, twenty-one billion, two hundred eighty-four million, two hundred fifty-two thousand, nine hundred seventeen".