13021344024440 has 16 divisors (see below), whose sum is σ = 29298024055080. Its totient is φ = 5208537609760.

The previous prime is 13021344024407. The next prime is 13021344024461. The reversal of 13021344024440 is 4442044312031.

It is a junction number, because it is equal to n+sod(n) for n = 13021344024397 and 13021344024406.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162766800266 + ... + 162766800345.

Almost surely, 2^{13021344024440} is an apocalyptic number.

13021344024440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13021344024440 is an abundant number, since it is smaller than the sum of its proper divisors (16276680030640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13021344024440 is a wasteful number, since it uses less digits than its factorization.

13021344024440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 325533600622 (or 325533600618 counting only the distinct ones).

The product of its (nonzero) digits is 36864, while the sum is 32.

Adding to 13021344024440 its reverse (4442044312031), we get a palindrome (17463388336471).

The spelling of 13021344024440 in words is "thirteen trillion, twenty-one billion, three hundred forty-four million, twenty-four thousand, four hundred forty".