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130214597 is a prime number
BaseRepresentation
bin1111100001011…
…10101011000101
3100002000120211212
413300232223011
5231313331342
620530541205
73140543252
oct760565305
9302016755
10130214597
1167559177
1237737805
1320c92376
1413418429
15b672182
hex7c2eac5

130214597 has 2 divisors, whose sum is σ = 130214598. Its totient is φ = 130214596.

The previous prime is 130214537. The next prime is 130214599. The reversal of 130214597 is 795412031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127554436 + 2660161 = 11294^2 + 1631^2 .

It is a cyclic number.

It is not a de Polignac number, because 130214597 - 212 = 130210501 is a prime.

Together with 130214599, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130214599) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65107298 + 65107299.

It is an arithmetic number, because the mean of its divisors is an integer number (65107299).

Almost surely, 2130214597 is an apocalyptic number.

It is an amenable number.

130214597 is a deficient number, since it is larger than the sum of its proper divisors (1).

130214597 is an equidigital number, since it uses as much as digits as its factorization.

130214597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7560, while the sum is 32.

The square root of 130214597 is about 11411.1610715124. The cubic root of 130214597 is about 506.8582935031.

The spelling of 130214597 in words is "one hundred thirty million, two hundred fourteen thousand, five hundred ninety-seven".