Base | Representation |
---|---|
bin | 1011110101111110110100… |
… | …0000001001100000010100 |
3 | 1201002220010002222210111102 |
4 | 2331133231000021200110 |
5 | 3201323100130111200 |
6 | 43410122342525232 |
7 | 2512544563440344 |
oct | 275375500114024 |
9 | 51086102883442 |
10 | 13022022113300 |
11 | 4170676aaa432 |
12 | 1563908a36818 |
13 | 735c822806a5 |
14 | 3303aaac0d24 |
15 | 178aecbd26d5 |
hex | bd7ed009814 |
13022022113300 has 72 divisors (see below), whose sum is σ = 28327077576000. Its totient is φ = 5196045945600.
The previous prime is 13022022113299. The next prime is 13022022113329. The reversal of 13022022113300 is 331122022031.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 113764697 + ... + 113879103.
It is an arithmetic number, because the mean of its divisors is an integer number (393431633000).
Almost surely, 213022022113300 is an apocalyptic number.
13022022113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13022022113300 is an abundant number, since it is smaller than the sum of its proper divisors (15305055462700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13022022113300 is a wasteful number, since it uses less digits than its factorization.
13022022113300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117201 (or 117194 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13022022113300 its reverse (331122022031), we get a palindrome (13353144135331).
The spelling of 13022022113300 in words is "thirteen trillion, twenty-two billion, twenty-two million, one hundred thirteen thousand, three hundred".
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