Base | Representation |
---|---|
bin | 111100101001001010… |
… | …0011011010111000101 |
3 | 110110010221220211002021 |
4 | 1321102110123113011 |
5 | 4113202401334131 |
6 | 135454335043141 |
7 | 12260136426664 |
oct | 1712224332705 |
9 | 413127824067 |
10 | 130230105541 |
11 | 502595548a8 |
12 | 212a59704b1 |
13 | c38576cb63 |
14 | 6435c86ddb |
15 | 35c3167e11 |
hex | 1e5251b5c5 |
130230105541 has 2 divisors, whose sum is σ = 130230105542. Its totient is φ = 130230105540.
The previous prime is 130230105527. The next prime is 130230105553. The reversal of 130230105541 is 145501032031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 86953624641 + 43276480900 = 294879^2 + 208030^2 .
It is a cyclic number.
It is not a de Polignac number, because 130230105541 - 221 = 130228008389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130230105581) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65115052770 + 65115052771.
It is an arithmetic number, because the mean of its divisors is an integer number (65115052771).
Almost surely, 2130230105541 is an apocalyptic number.
It is an amenable number.
130230105541 is a deficient number, since it is larger than the sum of its proper divisors (1).
130230105541 is an equidigital number, since it uses as much as digits as its factorization.
130230105541 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 130230105541 its reverse (145501032031), we get a palindrome (275731137572).
The spelling of 130230105541 in words is "one hundred thirty billion, two hundred thirty million, one hundred five thousand, five hundred forty-one".
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