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130301112222030 = 23510867399684403
BaseRepresentation
bin11101101000001000010111…
…100000100000000101001110
3122002100122221112210001022110
4131220020113200200011032
5114034323134212101110
61141043300553524450
736305642013313011
oct3550102740400516
9562318845701273
10130301112222030
11385774339a7392
121274528aa13726
13579245a953829
142426870d01378
15100e66e704a20
hex76821782014e

130301112222030 has 32 divisors (see below), whose sum is σ = 312751447392384. Its totient is φ = 34743765697056.

The previous prime is 130301112222023. The next prime is 130301112222037. The reversal of 130301112222030 is 30222211103031.

It is an interprime number because it is at equal distance from previous prime (130301112222023) and next prime (130301112222037).

It is a super-3 number, since 3×1303011122220303 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130301112221988 and 130301112222006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130301112222037) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 199516192 + ... + 200168211.

It is an arithmetic number, because the mean of its divisors is an integer number (9773482731012).

Almost surely, 2130301112222030 is an apocalyptic number.

130301112222030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130301112222030 is an abundant number, since it is smaller than the sum of its proper divisors (182450335170354).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130301112222030 is a wasteful number, since it uses less digits than its factorization.

130301112222030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 399695280.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 130301112222030 its reverse (30222211103031), we get a palindrome (160523323325061).

The spelling of 130301112222030 in words is "one hundred thirty trillion, three hundred one billion, one hundred twelve million, two hundred twenty-two thousand, thirty".

Divisors: 1 2 3 5 6 10 15 30 10867 21734 32601 54335 65202 108670 163005 326010 399684403 799368806 1199053209 1998422015 2398106418 3996844030 5995266045 11990532090 4343370407401 8686740814802 13030111222203 21716852037005 26060222444406 43433704074010 65150556111015 130301112222030