Base | Representation |
---|---|
bin | 11101101000010101110011… |
… | …001011000101110011100110 |
3 | 122002102001011200210212000010 |
4 | 131220111303023011303212 |
5 | 114040042203430441032 |
6 | 1141054044052231050 |
7 | 36306662304114351 |
oct | 3550256313056346 |
9 | 562361150725003 |
10 | 130315535015142 |
11 | 38582565219314 |
12 | 1274803500b486 |
13 | 5793918a24839 |
14 | 242743c5d3298 |
15 | 100ec159eeccc |
hex | 7685732c5ce6 |
130315535015142 has 32 divisors (see below), whose sum is σ = 274361120092800. Its totient is φ = 41150380416768.
The previous prime is 130315535015131. The next prime is 130315535015147. The reversal of 130315535015142 is 241510535513031.
It is a self number, because there is not a number n which added to its sum of digits gives 130315535015142.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130315535015147) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23813643 + ... + 28770134.
It is an arithmetic number, because the mean of its divisors is an integer number (8573785002900).
Almost surely, 2130315535015142 is an apocalyptic number.
130315535015142 is an abundant number, since it is smaller than the sum of its proper divisors (144045585077658).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130315535015142 is a wasteful number, since it uses less digits than its factorization.
130315535015142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52605540.
The product of its (nonzero) digits is 135000, while the sum is 39.
The spelling of 130315535015142 in words is "one hundred thirty trillion, three hundred fifteen billion, five hundred thirty-five million, fifteen thousand, one hundred forty-two".
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