Base | Representation |
---|---|
bin | 11101101000100101001111… |
… | …010111011100011100110110 |
3 | 122002110121222010100210220202 |
4 | 131220211033113130130312 |
5 | 114040330132210034110 |
6 | 1141105425140400502 |
7 | 36311120200303232 |
oct | 3550451727343466 |
9 | 562417863323822 |
10 | 130332114143030 |
11 | 385895a27564a8 |
12 | 1274b2a13a6132 |
13 | 579535b779297 |
14 | 24281724375c2 |
15 | 101038628e0a5 |
hex | 76894f5dc736 |
130332114143030 has 64 divisors (see below), whose sum is σ = 248490045330048. Its totient is φ = 49047965890560.
The previous prime is 130332114143017. The next prime is 130332114143089. The reversal of 130332114143030 is 30341411233031.
It is a junction number, because it is equal to n+sod(n) for n = 130332114142984 and 130332114143002.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8322073400 + ... + 8322089060.
It is an arithmetic number, because the mean of its divisors is an integer number (3882656958282).
Almost surely, 2130332114143030 is an apocalyptic number.
130332114143030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130332114143030 is a deficient number, since it is larger than the sum of its proper divisors (118157931187018).
130332114143030 is a wasteful number, since it uses less digits than its factorization.
130332114143030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30761.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 130332114143030 its reverse (30341411233031), we get a palindrome (160673525376061).
The spelling of 130332114143030 in words is "one hundred thirty trillion, three hundred thirty-two billion, one hundred fourteen million, one hundred forty-three thousand, thirty".
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