Base | Representation |
---|---|
bin | 10010111101110101001… |
… | …000000100101000101111 |
3 | 11121121011000102012102220 |
4 | 102331311020010220233 |
5 | 132323220034003403 |
6 | 2434425102250423 |
7 | 163106661260160 |
oct | 22756510045057 |
9 | 4547130365386 |
10 | 1303340141103 |
11 | 46281a593690 |
12 | 190719b86a13 |
13 | 95b9b0c25b0 |
14 | 47121013767 |
15 | 23d822a6953 |
hex | 12f75204a2f |
1303340141103 has 96 divisors (see below), whose sum is σ = 2398025064960. Its totient is φ = 608085066240.
The previous prime is 1303340141087. The next prime is 1303340141167. The reversal of 1303340141103 is 3011410433031.
It is not a de Polignac number, because 1303340141103 - 24 = 1303340141087 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1303340141503) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3952593 + ... + 4269621.
It is an arithmetic number, because the mean of its divisors is an integer number (24979427760).
Almost surely, 21303340141103 is an apocalyptic number.
1303340141103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1303340141103 is a deficient number, since it is larger than the sum of its proper divisors (1094684923857).
1303340141103 is a wasteful number, since it uses less digits than its factorization.
1303340141103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 317137 (or 317100 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 1303340141103 its reverse (3011410433031), we get a palindrome (4314750574134).
The spelling of 1303340141103 in words is "one trillion, three hundred three billion, three hundred forty million, one hundred forty-one thousand, one hundred three".
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