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13040234041200 = 24352292741136709
BaseRepresentation
bin1011110111000010101010…
…0001001000111101110000
31201011122010022221120221120
42331300222201020331300
53202122344403304300
643422333435422240
72514061104326142
oct275605241107560
951148108846846
1013040234041200
114178372181413
12156734bbb4980
137378c53834a2
14331217716c92
1517931699e3a0
hexbdc2a848f70

13040234041200 has 240 divisors, whose sum is σ = 43228719122400. Its totient is φ = 3356236083200.

The previous prime is 13040234041181. The next prime is 13040234041207. The reversal of 13040234041200 is 214043204031.

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13040234041207) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 95318446 + ... + 95455154.

It is an arithmetic number, because the mean of its divisors is an integer number (180119663010).

Almost surely, 213040234041200 is an apocalyptic number.

13040234041200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13040234041200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21614359561200).

13040234041200 is an abundant number, since it is smaller than the sum of its proper divisors (30188485081200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13040234041200 is a wasteful number, since it uses less digits than its factorization.

13040234041200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 139500 (or 139489 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13040234041200 its reverse (214043204031), we get a palindrome (13254277245231).

The spelling of 13040234041200 in words is "thirteen trillion, forty billion, two hundred thirty-four million, forty-one thousand, two hundred".