130419941 has 2 divisors, whose sum is σ = 130419942. Its totient is φ = 130419940.

The previous prime is 130419929. The next prime is 130419973. The reversal of 130419941 is 149914031.

It is an a-pointer prime, because the next prime (130419973) can be obtained adding 130419941 to its sum of digits (32).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127215841 + 3204100 = 11279^2 + 1790^2 .

It is a cyclic number.

It is not a de Polignac number, because 130419941 - 2²² = 126225637 is a prime.

It is a super-2 number, since 2×130419941² = 34018722020886962, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130419898 and 130419907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130419041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65209970 + 65209971.

It is an arithmetic number, because the mean of its divisors is an integer number (65209971).

Almost surely, 2^130419941 is an apocalyptic number.

It is an amenable number.

130419941 is a deficient number, since it is larger than the sum of its proper divisors (1).

130419941 is an equidigital number, since it uses as much as digits as its factorization.

130419941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 32.

The square root of 130419941 is about 11420.1550339739. The cubic root of 130419941 is about 507.1245863493.

The spelling of 130419941 in words is "one hundred thirty million, four hundred nineteen thousand, nine hundred forty-one".