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13042025000 = 23552917989
BaseRepresentation
bin11000010010101110…
…11000001000101000
31020122220212111220222
430021113120020220
5203202224300000
65554051505212
7641123245334
oct141127301050
936586774828
1013042025000
115592979464
12263b8b8208
1312cacc7174
148ba1887c4
15514ea3a85
hex3095d8228

13042025000 has 96 divisors (see below), whose sum is σ = 31621023000. Its totient is φ = 5036640000.

The previous prime is 13042024999. The next prime is 13042025039. The reversal of 13042025000 is 52024031.

It can be written as a sum of positive squares in 12 ways, for example, as 4050813316 + 8991211684 = 63646^2 + 94822^2 .

It is a super-2 number, since 2×130420250002 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13042025000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 716006 + ... + 733994.

Almost surely, 213042025000 is an apocalyptic number.

13042025000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13042025000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15810511500).

13042025000 is an abundant number, since it is smaller than the sum of its proper divisors (18578998000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13042025000 is an equidigital number, since it uses as much as digits as its factorization.

13042025000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18049 (or 18025 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 17.

Adding to 13042025000 its reverse (52024031), we get a palindrome (13094049031).

The spelling of 13042025000 in words is "thirteen billion, forty-two million, twenty-five thousand".

Divisors: 1 2 4 5 8 10 20 25 29 40 50 58 100 116 125 145 200 232 250 290 500 580 625 725 1000 1160 1250 1450 2500 2900 3125 3625 5000 5800 6250 7250 12500 14500 17989 18125 25000 29000 35978 36250 71956 72500 89945 90625 143912 145000 179890 181250 359780 362500 449725 521681 719560 725000 899450 1043362 1798900 2086724 2248625 2608405 3597800 4173448 4497250 5216810 8994500 10433620 11243125 13042025 17989000 20867240 22486250 26084050 44972500 52168100 56215625 65210125 89945000 104336200 112431250 130420250 224862500 260840500 326050625 449725000 521681000 652101250 1304202500 1630253125 2608405000 3260506250 6521012500 13042025000