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13042108296157 is a prime number
BaseRepresentation
bin1011110111001001101000…
…1110110110101111011101
31201011210221221200121101211
42331302122032312233131
53202140214210434112
643423243431304421
72514155413251253
oct275623216665735
951153857617354
1013042108296157
114179144142956
12156779381b111
13737b337719a5
143313545dc5d3
151793c62c40a7
hexbdc9a3b6bdd

13042108296157 has 2 divisors, whose sum is σ = 13042108296158. Its totient is φ = 13042108296156.

The previous prime is 13042108296067. The next prime is 13042108296179. The reversal of 13042108296157 is 75169280124031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12895036813156 + 147071483001 = 3590966^2 + 383499^2 .

It is a cyclic number.

It is not a de Polignac number, because 13042108296157 - 223 = 13042099907549 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13042108296157.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13042108296197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521054148078 + 6521054148079.

It is an arithmetic number, because the mean of its divisors is an integer number (6521054148079).

It is a 1-persistent number, because it is pandigital, but 2⋅13042108296157 = 26084216592314 is not.

Almost surely, 213042108296157 is an apocalyptic number.

It is an amenable number.

13042108296157 is a deficient number, since it is larger than the sum of its proper divisors (1).

13042108296157 is an equidigital number, since it uses as much as digits as its factorization.

13042108296157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 725760, while the sum is 49.

The spelling of 13042108296157 in words is "thirteen trillion, forty-two billion, one hundred eight million, two hundred ninety-six thousand, one hundred fifty-seven".