13042108296197 has 2 divisors, whose sum is σ = 13042108296198. Its totient is φ = 13042108296196.

The previous prime is 13042108296179. The next prime is 13042108296199. The reversal of 13042108296197 is 79169280124031.

Together with previous prime (13042108296179) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9063176481121 + 3978931815076 = 3010511^2 + 1994726^2 .

It is an emirp because it is prime and its reverse (79169280124031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13042108296197 - 2²⁸ = 13041839860741 is a prime.

It is a super-2 number, since 2×13042108296197² (a number of 27 digits) contains 22 as substring.

Together with 13042108296199, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13042108296199) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521054148098 + 6521054148099.

It is an arithmetic number, because the mean of its divisors is an integer number (6521054148099).

Almost surely, 2^{13042108296197} is an apocalyptic number.

It is an amenable number.

13042108296197 is a deficient number, since it is larger than the sum of its proper divisors (1).

13042108296197 is an equidigital number, since it uses as much as digits as its factorization.

13042108296197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1306368, while the sum is 53.

The spelling of 13042108296197 in words is "thirteen trillion, forty-two billion, one hundred eight million, two hundred ninety-six thousand, one hundred ninety-seven".