130423525247 has 2 divisors, whose sum is σ = 130423525248. Its totient is φ = 130423525246.

The previous prime is 130423525129. The next prime is 130423525249. The reversal of 130423525247 is 742525324031.

It is a strong prime.

It is an emirp because it is prime and its reverse (742525324031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130423525247 - 2¹⁶ = 130423459711 is a prime.

It is a super-2 number, since 2×130423525247² (a number of 23 digits) contains 22 as substring.

Together with 130423525249, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130423525247.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130423525249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65211762623 + 65211762624.

It is an arithmetic number, because the mean of its divisors is an integer number (65211762624).

Almost surely, 2^130423525247 is an apocalyptic number.

130423525247 is a deficient number, since it is larger than the sum of its proper divisors (1).

130423525247 is an equidigital number, since it uses as much as digits as its factorization.

130423525247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 201600, while the sum is 38.

Adding to 130423525247 its reverse (742525324031), we get a palindrome (872948849278).

The spelling of 130423525247 in words is "one hundred thirty billion, four hundred twenty-three million, five hundred twenty-five thousand, two hundred forty-seven".