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1304251514341 is a prime number
BaseRepresentation
bin10010111110101011011…
…100101011110111100101
311121200111112022202111021
4102332223130223313211
5132332101341424331
62435055340211141
7163141365645046
oct22765334536745
94550445282437
101304251514341
11463147a83906
12190933239ab1
1395cb4b6b8b9
14471aa0908cd
1523dd72cd211
hex12fab72bde5

1304251514341 has 2 divisors, whose sum is σ = 1304251514342. Its totient is φ = 1304251514340.

The previous prime is 1304251514339. The next prime is 1304251514353. The reversal of 1304251514341 is 1434151524031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1057769053441 + 246482460900 = 1028479^2 + 496470^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304251514341 - 21 = 1304251514339 is a prime.

Together with 1304251514339, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1304251514297 and 1304251514306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304251514941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652125757170 + 652125757171.

It is an arithmetic number, because the mean of its divisors is an integer number (652125757171).

Almost surely, 21304251514341 is an apocalyptic number.

It is an amenable number.

1304251514341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304251514341 is an equidigital number, since it uses as much as digits as its factorization.

1304251514341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 34.

The spelling of 1304251514341 in words is "one trillion, three hundred four billion, two hundred fifty-one million, five hundred fourteen thousand, three hundred forty-one".