13044112117 has 2 divisors, whose sum is σ = 13044112118. Its totient is φ = 13044112116.

The previous prime is 13044112111. The next prime is 13044112181. The reversal of 13044112117 is 71121144031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6734828356 + 6309283761 = 82066^2 + 79431^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044112117 - 2¹¹ = 13044110069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13044112091 and 13044112100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13044112111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522056058 + 6522056059.

It is an arithmetic number, because the mean of its divisors is an integer number (6522056059).

Almost surely, 2^13044112117 is an apocalyptic number.

It is an amenable number.

13044112117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044112117 is an equidigital number, since it uses as much as digits as its factorization.

13044112117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 672, while the sum is 25.

Adding to 13044112117 its reverse (71121144031), we get a palindrome (84165256148).

The spelling of 13044112117 in words is "thirteen billion, forty-four million, one hundred twelve thousand, one hundred seventeen".