13044112181 has 2 divisors, whose sum is σ = 13044112182. Its totient is φ = 13044112180.

The previous prime is 13044112117. The next prime is 13044112183. The reversal of 13044112181 is 18121144031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11032141156 + 2011971025 = 105034^2 + 44855^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044112181 - 2⁶ = 13044112117 is a prime.

It is a super-2 number, since 2×13044112181² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 13044112183, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13044112181.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13044112183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522056090 + 6522056091.

It is an arithmetic number, because the mean of its divisors is an integer number (6522056091).

Almost surely, 2^13044112181 is an apocalyptic number.

It is an amenable number.

13044112181 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044112181 is an equidigital number, since it uses as much as digits as its factorization.

13044112181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 26.

The spelling of 13044112181 in words is "thirteen billion, forty-four million, one hundred twelve thousand, one hundred eighty-one".