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1304414143 is a prime number
BaseRepresentation
bin100110110111111…
…1100011110111111
310100220111002210221
41031233330132333
510132412223033
6333234042211
744216223454
oct11557743677
93326432727
101304414143
1160a34271a
12304a19367
1317a3221b6
14c534d82b
15797b312d
hex4dbfc7bf

1304414143 has 2 divisors, whose sum is σ = 1304414144. Its totient is φ = 1304414142.

The previous prime is 1304414141. The next prime is 1304414149. The reversal of 1304414143 is 3414144031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1304414143 - 21 = 1304414141 is a prime.

Together with 1304414141, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304414141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652207071 + 652207072.

It is an arithmetic number, because the mean of its divisors is an integer number (652207072).

Almost surely, 21304414143 is an apocalyptic number.

1304414143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304414143 is an equidigital number, since it uses as much as digits as its factorization.

1304414143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

The square root of 1304414143 is about 36116.6740301485. The cubic root of 1304414143 is about 1092.6267604576.

Adding to 1304414143 its reverse (3414144031), we get a palindrome (4718558174).

The spelling of 1304414143 in words is "one billion, three hundred four million, four hundred fourteen thousand, one hundred forty-three".