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13050107568319 is a prime number
BaseRepresentation
bin1011110111100111011100…
…0001101010000010111111
31201012120121102201201220011
42331321313001222002333
53202303110014141234
643431045303404051
72514560555040403
oct275716701520277
951176542651804
1013050107568319
114181579563488
121569246753627
13738809abb723
143318b2b57103
151796e36c8b64
hexbde7706a0bf

13050107568319 has 2 divisors, whose sum is σ = 13050107568320. Its totient is φ = 13050107568318.

The previous prime is 13050107568317. The next prime is 13050107568431. The reversal of 13050107568319 is 91386570105031.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13050107568319 - 21 = 13050107568317 is a prime.

It is a super-2 number, since 2×130501075683192 (a number of 27 digits) contains 22 as substring.

Together with 13050107568317, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13050107568317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6525053784159 + 6525053784160.

It is an arithmetic number, because the mean of its divisors is an integer number (6525053784160).

Almost surely, 213050107568319 is an apocalyptic number.

13050107568319 is a deficient number, since it is larger than the sum of its proper divisors (1).

13050107568319 is an equidigital number, since it uses as much as digits as its factorization.

13050107568319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 680400, while the sum is 49.

The spelling of 13050107568319 in words is "thirteen trillion, fifty billion, one hundred seven million, five hundred sixty-eight thousand, three hundred nineteen".