Base | Representation |
---|---|
bin | 100110111001001… |
… | …0000011011010000 |
3 | 10100221121220001020 |
4 | 1031302100123100 |
5 | 10133041120422 |
6 | 333255035440 |
7 | 44224326234 |
oct | 11562203320 |
9 | 3327556036 |
10 | 1305020112 |
11 | 60a716a20 |
12 | 30506bb80 |
13 | 17a4a4c66 |
14 | c546a5c4 |
15 | 7988295c |
hex | 4dc906d0 |
1305020112 has 40 divisors (see below), whose sum is σ = 3677785440. Its totient is φ = 395460480.
The previous prime is 1305020107. The next prime is 1305020117. The reversal of 1305020112 is 2110205031.
It is an interprime number because it is at equal distance from previous prime (1305020107) and next prime (1305020117).
It is a junction number, because it is equal to n+sod(n) for n = 1305020091 and 1305020100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1305020117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1235287 + ... + 1236342.
It is an arithmetic number, because the mean of its divisors is an integer number (91944636).
Almost surely, 21305020112 is an apocalyptic number.
1305020112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1305020112 is an abundant number, since it is smaller than the sum of its proper divisors (2372765328).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1305020112 is a wasteful number, since it uses less digits than its factorization.
1305020112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2471651 (or 2471645 counting only the distinct ones).
The product of its (nonzero) digits is 60, while the sum is 15.
The square root of 1305020112 is about 36125.0621037528. The cubic root of 1305020112 is about 1092.7959284705.
Adding to 1305020112 its reverse (2110205031), we get a palindrome (3415225143).
The spelling of 1305020112 in words is "one billion, three hundred five million, twenty thousand, one hundred twelve".
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