Base | Representation |
---|---|
bin | 11000010011101110… |
… | …10101110111101101 |
3 | 1020200111122020012122 |
4 | 30021313111313231 |
5 | 203211400414313 |
6 | 5554551242325 |
7 | 641254415021 |
oct | 141167256755 |
9 | 36614566178 |
10 | 13050404333 |
11 | 5597681a2a |
12 | 26426793a5 |
13 | 12cc96c155 |
14 | 8bb32a381 |
15 | 515aab708 |
hex | 309dd5ded |
13050404333 has 2 divisors, whose sum is σ = 13050404334. Its totient is φ = 13050404332.
The previous prime is 13050404293. The next prime is 13050404351. The reversal of 13050404333 is 33340405031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11907829129 + 1142575204 = 109123^2 + 33802^2 .
It is a cyclic number.
It is not a de Polignac number, because 13050404333 - 28 = 13050404077 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13050404383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6525202166 + 6525202167.
It is an arithmetic number, because the mean of its divisors is an integer number (6525202167).
Almost surely, 213050404333 is an apocalyptic number.
It is an amenable number.
13050404333 is a deficient number, since it is larger than the sum of its proper divisors (1).
13050404333 is an equidigital number, since it uses as much as digits as its factorization.
13050404333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 26.
Adding to 13050404333 its reverse (33340405031), we get a palindrome (46390809364).
The spelling of 13050404333 in words is "thirteen billion, fifty million, four hundred four thousand, three hundred thirty-three".
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