130520111 has 2 divisors, whose sum is σ = 130520112. Its totient is φ = 130520110.

The previous prime is 130520099. The next prime is 130520113. The reversal of 130520111 is 111025031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130520111 is a prime.

Together with 130520113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130520113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65260055 + 65260056.

It is an arithmetic number, because the mean of its divisors is an integer number (65260056).

Almost surely, 2^130520111 is an apocalyptic number.

130520111 is a deficient number, since it is larger than the sum of its proper divisors (1).

130520111 is an equidigital number, since it uses as much as digits as its factorization.

130520111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30, while the sum is 14.

The square root of 130520111 is about 11424.5398594429. The cubic root of 130520111 is about 507.2543867196.

Adding to 130520111 its reverse (111025031), we get a palindrome (241545142).

The spelling of 130520111 in words is "one hundred thirty million, five hundred twenty thousand, one hundred eleven".