Base | Representation |
---|---|
bin | 10010111111110001010… |
… | …010000101101000110111 |
3 | 11121210112011221120201012 |
4 | 102333301102011220313 |
5 | 132342001311011211 |
6 | 2435411512222435 |
7 | 163212413422343 |
oct | 22776122055067 |
9 | 4553464846635 |
10 | 1305423141431 |
11 | 463699370662 |
12 | 190bbb69aa1b |
13 | 9614080a876 |
14 | 4727b916623 |
15 | 23e550b1d8b |
hex | 12ff1485a37 |
1305423141431 has 2 divisors, whose sum is σ = 1305423141432. Its totient is φ = 1305423141430.
The previous prime is 1305423141409. The next prime is 1305423141433. The reversal of 1305423141431 is 1341413245031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1305423141431 is a prime.
It is a super-2 number, since 2×13054231414312 (a number of 25 digits) contains 22 as substring.
Together with 1305423141433, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1305423141433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652711570715 + 652711570716.
It is an arithmetic number, because the mean of its divisors is an integer number (652711570716).
Almost surely, 21305423141431 is an apocalyptic number.
1305423141431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305423141431 is an equidigital number, since it uses as much as digits as its factorization.
1305423141431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 1305423141431 its reverse (1341413245031), we get a palindrome (2646836386462).
The spelling of 1305423141431 in words is "one trillion, three hundred five billion, four hundred twenty-three million, one hundred forty-one thousand, four hundred thirty-one".
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