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13054311400 = 23521316330803
BaseRepresentation
bin11000010100001100…
…01111101111101000
31020200202222201200211
430022012033233220
5203213400431100
65555211110504
7641332546624
oct141206175750
936622881624
1013054311400
115599900409
122643a42434
131300709620
148bba66184
155160ce1ba
hex30a18fbe8

13054311400 has 96 divisors (see below), whose sum is σ = 32887582560. Its totient is φ = 4790327040.

The previous prime is 13054311397. The next prime is 13054311419. The reversal of 13054311400 is 411345031.

13054311400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×130543114002 (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 408399 + ... + 439201.

It is an arithmetic number, because the mean of its divisors is an integer number (342578985).

Almost surely, 213054311400 is an apocalyptic number.

13054311400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13054311400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16443791280).

13054311400 is an abundant number, since it is smaller than the sum of its proper divisors (19833271160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13054311400 is a wasteful number, since it uses less digits than its factorization.

13054311400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30995 (or 30986 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 13054311400 its reverse (411345031), we get a palindrome (13465656431).

The spelling of 13054311400 in words is "thirteen billion, fifty-four million, three hundred eleven thousand, four hundred".

Divisors: 1 2 4 5 8 10 13 20 25 26 40 50 52 65 100 104 130 163 200 260 325 326 520 650 652 815 1300 1304 1630 2119 2600 3260 4075 4238 6520 8150 8476 10595 16300 16952 21190 30803 32600 42380 52975 61606 84760 105950 123212 154015 211900 246424 308030 400439 423800 616060 770075 800878 1232120 1540150 1601756 2002195 3080300 3203512 4004390 5020889 6160600 8008780 10010975 10041778 16017560 20021950 20083556 25104445 40043900 40167112 50208890 65271557 80087800 100417780 125522225 130543114 200835560 251044450 261086228 326357785 502088900 522172456 652715570 1004177800 1305431140 1631788925 2610862280 3263577850 6527155700 13054311400