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1305513423050 = 25297649267389
BaseRepresentation
bin10010111111110110101…
…010011111000011001010
311121210202110211100210212
4102333312222133003022
5132342142414014200
62435424455241122
7163214561000144
oct22776652370312
94553673740725
101305513423050
11463735324571
121910259791a2
139615642aa45
14472898d7c94
1523e5ce97035
hex12ff6a9f0ca

1305513423050 has 24 divisors (see below), whose sum is σ = 2428288915500. Its totient is φ = 522198068480.

The previous prime is 1305513423043. The next prime is 1305513423079. The reversal of 1305513423050 is 503243155031.

It can be written as a sum of positive squares in 6 ways, for example, as 1125358167241 + 180155255809 = 1060829^2 + 424447^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1305513422998 and 1305513423016.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4748756 + ... + 5016144.

Almost surely, 21305513423050 is an apocalyptic number.

1305513423050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1305513423050 is a deficient number, since it is larger than the sum of its proper divisors (1122775492450).

1305513423050 is a wasteful number, since it uses less digits than its factorization.

1305513423050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 365050 (or 365045 counting only the distinct ones).

The product of its (nonzero) digits is 27000, while the sum is 32.

Adding to 1305513423050 its reverse (503243155031), we get a palindrome (1808756578081).

The spelling of 1305513423050 in words is "one trillion, three hundred five billion, five hundred thirteen million, four hundred twenty-three thousand, fifty".

Divisors: 1 2 5 10 25 50 97649 195298 267389 488245 534778 976490 1336945 2441225 2673890 4882450 6684725 13369450 26110268461 52220536922 130551342305 261102684610 652756711525 1305513423050