Base | Representation |
---|---|
bin | 111100110100111011… |
… | …1110111011000011000 |
3 | 110111011111111022121212 |
4 | 1321221313313120120 |
5 | 4120010032140240 |
6 | 140001452522252 |
7 | 12303005325545 |
oct | 1715167673030 |
9 | 414144438555 |
10 | 130625271320 |
11 | 50441618795 |
12 | 21396180388 |
13 | c4195aac6b |
14 | 647254dbcc |
15 | 35e7bc4165 |
hex | 1e69df7618 |
130625271320 has 32 divisors (see below), whose sum is σ = 309375644400. Its totient is φ = 49500102528.
The previous prime is 130625271289. The next prime is 130625271323. The reversal of 130625271320 is 23172526031.
It is a super-2 number, since 2×1306252713202 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130625271323) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85936919 + ... + 85938438.
Almost surely, 2130625271320 is an apocalyptic number.
130625271320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130625271320 is an abundant number, since it is smaller than the sum of its proper divisors (178750373080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130625271320 is a wasteful number, since it uses less digits than its factorization.
130625271320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171875387 (or 171875383 counting only the distinct ones).
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 130625271320 its reverse (23172526031), we get a palindrome (153797797351).
The spelling of 130625271320 in words is "one hundred thirty billion, six hundred twenty-five million, two hundred seventy-one thousand, three hundred twenty".
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