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130778934047 is a prime number
BaseRepresentation
bin111100111001100001…
…0000010101100011111
3110111120012122012020222
41321303002002230133
54120313401342142
6140025022231555
712306552412046
oct1716302025437
9414505565228
10130778934047
1150510331883
12214197255bb
13c442390058
146488b0d55d
153606428bd2
hex1e73082b1f

130778934047 has 2 divisors, whose sum is σ = 130778934048. Its totient is φ = 130778934046.

The previous prime is 130778934023. The next prime is 130778934049. The reversal of 130778934047 is 740439877031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130778934047 - 220 = 130777885471 is a prime.

Together with 130778934049, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130778934047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130778934049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65389467023 + 65389467024.

It is an arithmetic number, because the mean of its divisors is an integer number (65389467024).

Almost surely, 2130778934047 is an apocalyptic number.

130778934047 is a deficient number, since it is larger than the sum of its proper divisors (1).

130778934047 is an equidigital number, since it uses as much as digits as its factorization.

130778934047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3556224, while the sum is 53.

The spelling of 130778934047 in words is "one hundred thirty billion, seven hundred seventy-eight million, nine hundred thirty-four thousand, forty-seven".