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130824134741 is a prime number
BaseRepresentation
bin111100111010110111…
…0011110000001010101
3110111200100200121221202
41321311232132001111
54120411434302431
6140033315122245
712310641540356
oct1716556360125
9414610617852
10130824134741
11505338a4823
12214308a3385
13c44b857b21
146490b17d2d
15360a3a68cb
hex1e75b9e055

130824134741 has 2 divisors, whose sum is σ = 130824134742. Its totient is φ = 130824134740.

The previous prime is 130824134731. The next prime is 130824134743. The reversal of 130824134741 is 147431428031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130458216100 + 365918641 = 361190^2 + 19129^2 .

It is a cyclic number.

It is not a de Polignac number, because 130824134741 - 26 = 130824134677 is a prime.

It is a super-2 number, since 2×1308241347412 (a number of 23 digits) contains 22 as substring.

Together with 130824134743, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130824134695 and 130824134704.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130824134743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65412067370 + 65412067371.

It is an arithmetic number, because the mean of its divisors is an integer number (65412067371).

Almost surely, 2130824134741 is an apocalyptic number.

It is an amenable number.

130824134741 is a deficient number, since it is larger than the sum of its proper divisors (1).

130824134741 is an equidigital number, since it uses as much as digits as its factorization.

130824134741 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64512, while the sum is 38.

The spelling of 130824134741 in words is "one hundred thirty billion, eight hundred twenty-four million, one hundred thirty-four thousand, seven hundred forty-one".