Base | Representation |
---|---|
bin | 11101110010010011010010… |
… | …111110000011011100100000 |
3 | 122011211111000011111001200121 |
4 | 131302103102332003130200 |
5 | 114132301041223313100 |
6 | 1142340331040530024 |
7 | 36410304106431013 |
oct | 3562232276033440 |
9 | 564744004431617 |
10 | 131000042010400 |
11 | 38816895607162 |
12 | 12838829020914 |
13 | 581333546c644 |
14 | 244c61601d37a |
15 | 102292985c51a |
hex | 7724d2f83720 |
131000042010400 has 72 divisors (see below), whose sum is σ = 319829479696944. Its totient is φ = 52395817785600.
The previous prime is 131000042010367. The next prime is 131000042010403. The reversal of 131000042010400 is 4010240000131.
It is a super-2 number, since 2×1310000420104002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is not an unprimeable number, because it can be changed into a prime (131000042010403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3438079 + ... + 16547521.
It is an arithmetic number, because the mean of its divisors is an integer number (4442076106902).
Almost surely, 2131000042010400 is an apocalyptic number.
131000042010400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131000042010400 is an abundant number, since it is smaller than the sum of its proper divisors (188829437686544).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131000042010400 is a wasteful number, since it uses less digits than its factorization.
131000042010400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13121954 (or 13121941 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 131000042010400 its reverse (4010240000131), we get a palindrome (135010282010531).
The spelling of 131000042010400 in words is "one hundred thirty-one trillion, forty-two million, ten thousand, four hundred".
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