Base | Representation |
---|---|
bin | 1011111010100001010110… |
… | …0100110011001001001000 |
3 | 1201101100102101010202120211 |
4 | 2332220111210303021020 |
5 | 3204112311112033000 |
6 | 43510021301330504 |
7 | 2521305341426545 |
oct | 276502544631110 |
9 | 51340371122524 |
10 | 13100012221000 |
11 | 41a07584226a1 |
12 | 1576a53706a34 |
13 | 740430b86603 |
14 | 334088947bcc |
15 | 17ab649d77ba |
hex | bea15933248 |
13100012221000 has 64 divisors (see below), whose sum is σ = 31366913086080. Its totient is φ = 5118144292800.
The previous prime is 13100012220991. The next prime is 13100012221003. The reversal of 13100012221000 is 12221000131.
It is a super-2 number, since 2×131000122210002 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13100012221003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 152282724 + ... + 152368723.
It is an arithmetic number, because the mean of its divisors is an integer number (490108016970).
Almost surely, 213100012221000 is an apocalyptic number.
13100012221000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13100012221000 is an abundant number, since it is smaller than the sum of its proper divisors (18266900865080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100012221000 is a wasteful number, since it uses less digits than its factorization.
13100012221000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 304651511 (or 304651497 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 13100012221000 its reverse (12221000131), we get a palindrome (13112233221131).
The spelling of 13100012221000 in words is "thirteen trillion, one hundred billion, twelve million, two hundred twenty-one thousand".
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