13100020010420 has 96 divisors (see below), whose sum is σ = 31851508469760. Its totient is φ = 4432935974400.

The previous prime is 13100020010419. The next prime is 13100020010437. The reversal of 13100020010420 is 2401002000131.

It is a super-2 number, since 2×13100020010420² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (14).

It is a junction number, because it is equal to n+sod(n) for n = 13100020010395 and 13100020010404.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3021101 + ... + 5943659.

It is an arithmetic number, because the mean of its divisors is an integer number (331786546560).

Almost surely, 2^{13100020010420} is an apocalyptic number.

13100020010420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13100020010420, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15925754234880).

13100020010420 is an abundant number, since it is smaller than the sum of its proper divisors (18751488459340).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100020010420 is a wasteful number, since it uses less digits than its factorization.

13100020010420 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2922993 (or 2922991 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 13100020010420 its reverse (2401002000131), we get a palindrome (15501022010551).

The spelling of 13100020010420 in words is "thirteen trillion, one hundred billion, twenty million, ten thousand, four hundred twenty".